Recent content by premed_love

Homework Statement The barrel of a compound microscope is 15.9 cm in length. The specimen will be mounted 1.17 cm from the objective, and the eyepiece has a 5.00 cm focal length. Determine the focal length of the objective lens.Homework Equations I am using the mirror equation. The Attempt at...

Homework Statement An object is placed 12.8 cm to the left of a diverging lens of focal length -6.35 cm. A converging lens of focal length 12.8 cm is placed a distance of d to the right of the diverging lens. Find the distance d that places the final image at infinity Homework Equations...

Because it's a concave mirror. The image is also real. Earlier I was thinking they would be different signs as 4.00 cm is moving closer. But then the concave part made me think the sign would be the same.

I think they will be the same sign.

I think they will be the same size

but 2.94 cm is off. I am so confused!

So you would think it be a simple mirror equation then: 1/10.7+1/4.0=1/f so 2.94

I was thinking the image should be real and on the same side which is why my Di would not be negative.1/10.7+1/14.7=1/f which is why I get eventually, I get 6.19. Are you trying to imply that my di is negative and my equation should be 1/10.7-1/14.7=1/f

The only information I am given is the one I have provided. I am told it is a concave mirror- that's it.

Homework Statement A light bulb is placed 10.7 cm in front of a concave mirror. When the concave mirror is replaced by a plane mirror in the same location, the bulb's image moves 4.00 cm closer to the mirror. Calculate the focal length of the concave mirror. [FONT=Courier New] I am given: do...

Yes, I checked. I did my work correctly and used the negative sign three times! However, I was getting a wrong answer due to sig figs. That was frustrating because I never thought I had to be careful of sig figs!

I was struggling with the problem. I showed you my work. However, if you are also confused then I can not do anything about that. You tell me how to do di/do which I have done. I am not sure whether your supposed to show a sign.

IN that case: it would be 52.175/74.0 = .70506 and that is wrong. Thank you for your help.

I was given do in the problem which was 74.0 cm, you may reread the problem to see if I am interpreting that correctly. I found di to be 52.175 which you said my math was right.