Recent content by pressurised

When dealing with a bar (fixed on one end), if it is hollow for a certain length from the edge and then turns solid up until the fixed point, can the condition of static equilibrium be used to find the reaction torque, just like you would of a bar with 2 different diameters. (Assuming all this...

Thank you I understand now. By compound I meant I was struggling to find the molar mass of the CO2 (compound) but it was far more straightforward than I initially thought. Another part I initially messed up on was failing to realize the figures were not for the molecular pairs O and N travel in...

I should have used Mj and xj, but the sum of Mi (is the molar mass of each component) multiplied by ni (the mole fraction). I actually split up the dry air into oxygen and nitrogen to carry out the calculation but it won't generate the correct answer for me? So I take it I shouldn't split up...

I'm really confused as to why, Mmix=ΣxniMi doesn't work with this?

I'm completely lost with this. But to what you said, is it 85.7% dry air and 14.3% CO2? Do you happen to know any text or video that explains this clearly?

I got 67.7% of the mixture is Nitrogen, 4.8% is Carbon and 27.5% is Oxygen?

I can't seem to get anywhere close to 31g/mol. I'm not sure how to really do this. I done (0.21*16)+(0.79+14)+(⅓*12*1/6)+(2/3*16*1/6) and got 16.86g/mol...

Homework Statement Homework Equations M=m/n p=nRT/V The Attempt at a Solution I am confused on getting the molar mass of the mixture, unless the answer is wrong. For nN2 I done 0.79*(3*10-3) which gave me 2.37*10-3kmol For nO2 I done the same but with 0.21 to get 6.3*10-4kmol The ntotal of...

Homework Statement Homework Equations Cf=0.0577(μ/xρUm)0.2 The Attempt at a Solution I've managed to do parts a) and b), however I don't believe my attempt at the first part is correct as I am using a different Cf than the value used in the mark scheme. The expression I made for the first...

Thank you!

I can't quite think of the name of it but I understand what you mean:sorry:. I would have thought ∫-(ρ0+kh)g dz would have been okay to use?

Homework Statement Homework Equations dp/dz=-ρg p=ρgh The Attempt at a Solution I've found the density at depth 3m using ρ=ρ0+kh, which gave me 1060kgm-3. I then put this value into ρgh to get 31195.8Pa which seems to be ≈+1000 off the answer. What is the correct mathematical way of...

Thank you! I continued and equated the difference in pressure with the hole blocked with p1-p2 and that gave me the correct answer for U. :)

I see. The pressure would be ρg(1.2) on the left and ρg(0.6) on the right?

I mean point 1 as in right at the top of the 1.8m surface. And what would it be with the liquid there too or if the liquid hadn't have been there? The pressure would be pA I think if it was blocked up?