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Velocity change by running engine for 1 year
So which one should I use then? The ln with mass ratio which gave me an answer of: 3411.02 m/s Or the a = f/m which gave me a change of : 3156 m/s- pridet8
- Post #6
- Forum: Introductory Physics Homework Help
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Velocity change by running engine for 1 year
******Velocity @ 3.156 x 10^6 seconds = (.0001m/s^2)*500s = 315.6m/s******** I meant (.0001m/s^2)*3.156 x 10^6- pridet8
- Post #4
- Forum: Introductory Physics Homework Help
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Velocity change by running engine for 1 year
So then the velocity change will be: a= Thrust/M Where Thrust = .02 N and M = 200kg = .0001 m/s^2 Velocity @ 3.156 x 10^6 seconds = (.0001m/s^2)*500s = 315.6m/s Then the velocity change will be from 20,000m/s - 315.6m/s = 19684.4 m/s- pridet8
- Post #3
- Forum: Introductory Physics Homework Help
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Velocity change by running engine for 1 year
Homework Statement A rocket engine has an exhaust velocity of 20,000 m/sec. The mass flow (dm/dt) rate is 1 milligram per second. a) What is the thrust produced by the engine? b) The engine propels a 200 kg space craft. What change in velocity is achievable by running the engine...- pridet8
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- Change Engine Running Velocity Year
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- Forum: Introductory Physics Homework Help