Recent content by Prone17
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How do I classify acids and bases in chemistry?
Can anyone explain to me how to determine whether a compound is a strong acid, weak acid, strong base, weak base, or amphoteric? Thanks! -
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Calculating Molarity of FeSCN with Given Moles and Known Reactants
the total volume would be 10 mL thanks guys, i got it from here (hopefully) :D- Prone17
- Post #4
- Forum: Biology and Chemistry Homework Help
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Calculating Molarity of FeSCN with Given Moles and Known Reactants
i combined 5 mL of 0.20 M Fe with 1 mL of 4.0x10^-4 M HSCN and 4 mL of 0.5 M HNO3 i am asked to find the molarity of FeSCN. i am given this statement: "The concentration of Fe is so high relative to that of HSCN that we can assume that all SCN present is in the complexed form, FeSCN. In...- Prone17
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- Chemistry Molarity
- Replies: 3
- Forum: Biology and Chemistry Homework Help
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Calculating Moles & Molarity of KHP & NaOH
yes i did assume that. but then i realized that to find the moles of KHP (part 1 of my question), i would divide the mass of KHP (0.737 g) by the molar mass of KHP (204.22 g/mol). is this correct? and yes, that link is exactly what i did in the experiment.- Prone17
- Post #5
- Forum: Biology and Chemistry Homework Help
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Calculating Moles & Molarity of KHP & NaOH
i'm not sure what that means. I'm just going by my lab book. i just know that the experiment was to titrate NaOH into KHP, and as far as i know, this was not a trick question. the bottle i took the KHP from said "KHP" on it.- Prone17
- Post #3
- Forum: Biology and Chemistry Homework Help
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Calculating Moles & Molarity of KHP & NaOH
what i did: 1) i put 0.737 g of KHP in a flask 2) then added ~25 mL of distilled water 3) and then titrated 34.06 mL of NaOH into it to get its equilibrium point, how would i find: 1. the moles of KHP, and 2. the molarity of NaOH? and would the molar mass have any significance? 1. the...- Prone17
- Thread
- Chemistry Experiment
- Replies: 6
- Forum: Biology and Chemistry Homework Help
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High School Confused about Spring PE Formula: Hooke's Law vs. 1/2 kx^2
when attempting questions with springs involved, i get confused with the spring PE formula. i know its a simple formula but i don't get the correct answers i know hooke's law is E = -kx but in class i was given the formula E = 1/2 kx^2 is there a different time to use each of these...