Calculating Molarity of FeSCN with Given Moles and Known Reactants

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Discussion Overview

The discussion revolves around calculating the molarity of the complex FeSCN formed from the reaction of Fe, HSCN, and HNO3. Participants explore the necessary steps to determine the molarity based on given moles and the total volume of the solution.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant describes combining specific volumes and molarities of Fe, HSCN, and HNO3 to form FeSCN and calculates the moles of HSCN based on its molarity.
  • Another participant asks for clarification on the final volume of the mixture to assist in calculating the molarity of FeSCN.
  • A third participant suggests that determining the total volume involves summing the volumes of the individual components used in the reaction.
  • The initial poster confirms the total volume of the mixture as 10 mL and expresses confidence in proceeding with the calculation.

Areas of Agreement / Disagreement

Participants generally agree on the approach to calculate the molarity, but the exact volume used in the molarity calculation is clarified through discussion.

Contextual Notes

The calculation assumes that all SCN is converted to FeSCN, and the total volume is based on the sum of the individual volumes used, which may not account for any volume changes upon mixing.

Who May Find This Useful

Students or individuals interested in chemistry calculations, particularly those involving molarity and reaction stoichiometry.

Prone17
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i combined 5 mL of 0.20 M Fe with 1 mL of 4.0x10^-4 M HSCN and 4 mL of 0.5 M HNO3

i am asked to find the molarity of FeSCN.

i am given this statement: "The concentration of Fe is so high relative to that of HSCN that we can assume that all SCN present is in the complexed form, FeSCN. In other words, HSCN is the liming reagent and the number of moles of HSCN added equals the number of moles of FeSCN that forms."

so i calculated the moles of HSCN by multiplying the molarity by the amount added -> (4.0x10^-4)(0.001) = 4.0x10^-7
apparently this is the same as the moles of FeSCN.

how do i find the molarity of FeSCN? i know the moles, so all i need is the volume (Liters), but i don't know how much to use in the equation... any suggestions?

Thanks
 
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You have mixed everything together, right? So what is the final volume of the mixture?
 
A matter of simple accounting for total volume of the prepared solution of FeSCN. Sum of the volumes used in preparing the solution.
 
the total volume would be 10 mL

thanks guys, i got it from here (hopefully) :D
 

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