Recent content by Protium_H1

You’re actually a beauty. I just solved it, thanks!

Do you mean that, in this system, either net torque or net force is zero?

You mean something like this? \Sigma \vec{\tau}_{x-direction} = -\hat{i}(2.10F_{NJ}+0.80F_{NL}+0.80F_{NB}) \Sigma \vec{\tau}_{z-direction}= \hat{k}(0.40F_{NJ}+0.80F_{NL}−0.80F_{NR}) \Sigma \vec{F}_{y-direction} = \hat{j}(F_{NL}+F_{NR}+F_{NJ}−Mg) But how can I combine these if they have...

Homework Statement A car is lifted vertically by a jack placed at the car's rear end 40cm off the central axis, so that the weight of the car is supported by the jack and the two front wheels. The distance between the front wheels is 1.60m, the distance from the axis connecting the two wheels...

Would I have to add these two equations up and square them? [3.0u2cosΦ]2 = [v - u2cos(45o)]2 [3.0u2sinΦ]2 = [u1sin(45o)]2 then, [3.0u2sinΦ]2 + [3.0u2cosΦ]2 = [u1sin(45o)]2 + [v - u2cos(45o)]2 9.0u22[cos2Φ + sin2Φ] = [u1sin(45o)]2 + [v - u2cos(45o)]2 9.0u22 = [u1sin(45o)]2 + [v - u2cos(45o)]2...

Homework Statement An atomic nucleous of mass m traveling with speed v collides elastically with a target particle of mass 3.0m (initially at rest) and is scattered at 45o (a). What are the final speeds of the two particles? Advice: eliminate the target particle's recoil angle by manipulating...