Recent content by QuarkDecay

Thanks a lot...! I'm quite desperate over this problem and I couldn't find the solution anywhere over the web. Been searching for it for three days. Now I hope I can solve the rest of it lol

My notes say that the Resolution of the Aperture(in the Electric field of the wave) is the Fourier transformation of the aperture. Then gives us the equation of the aperture: and says that for the circular aperture in particular also: My attempt at solving this: We know that the Fourier...

Suppose we have two charged particles A and B released in the center of the Mirror (where the field is minimum). If A's velocity direction is parallel with the Magnetic field of the mirror and B's velocity is perpendicular with the field, then which one is going to get trapped, or escape, or...

There is the equation: μ= Eu +Eg/2 +3/4kβTln(mu/mc) Eg is the band gap, but I don't understand what Eu stands for and how we can calculate it? Could it be the valence band?

This is what I was looking for. Not sure if I worded "sources" quite right. But it came from calculating the V0(trec)/VH(trec)~1.4x10^5

My notes from class say it. I didn't provide a source because this was the solution without the inflation correction, and also for the fact that this is not my main question.

It says that since there is homogeneity in the Universe's temperature, all these points must have come from one source (or a source close to each other?) at a certain time. Then it also calculates the number of these sources and it's ~105. But isn't that very dense mass right before the Big...

Thank you very much!

You're referring to the fact that I didn't write it like ρr=ao(t)4? I corrected it, so no need to mention it again. I know a is time dependent. Other than pointing it out again, I know the answer is in my op. I just don't understand how it came up.

Thanks. I found out how the redshift zeq came up from the a, but I still don't understand why (ρm/ ρr)teq = (ρm/ ρr)o * a(teq)/ ao Anyone has any idea? What's the issue with the densities and the a(teq)/ ao ? If we say ρm(t)/ ρr(t)= ρom * ao4 / ρor * ao3 then we get ρm(t)/ ρr(t)= ρom* ao/...

can I say a(t)= a(teq)/ao ? Doing the calculations this is what is missing for the equation mathematically, but not even sure if that's right to say about the expansion rates. I feel like I'm missing a property of how the different times in the expansion rate work. Like, are there three...

Yes, that's what I mean. The a in time now, just writing as ao instead of a(to) because that's the symbol we also use in class

Ok then ρm(t)= ροm/αo(t)3 and likewise for the ρr(t). Still doesn't explain why the equation turns this way. Also what zeq is.

We want to calculate the ao/a(teq) of the equilibrium point between ρm and ρr (ρm= ρr ) My book solves it this way; ρm(t) / ρr(t)= a(t) ⇒ ⇒ (ρm/ ρr)teq =1 = = (ρm/ ρr)o * a(teq)/ ao I don't understand the a(teq)/ ao part. If ρm(t)= ρο/αo3 and ρr(t)= ρο/αo4 then it should be ρm(t)/ ρr(t) =...

I'm talking about the hypothetical models I listed in that url. I know not all of them are true. But also you said we have different fluids at different times. I know that the matter and radiation density ratio change with time. This is what I was asking. Near the Big Bang time, the radiation...