Recent content by rabcdred

Yep. It seems that way. Thanks so much for all of your help. I really appreciate it.

I got V(resis)= 6.73V, V(ind)= 10.78V, V(capac)=3.36V. Maybe my current is wrong. I got Irms= 0.134589502.

Yes I did. However, I did not get any of the possible answer choices when I did V=Irms * Xl

Thanks. I took your advice but I still cannot get the correct answer. I calculated 6.7 volts being dissipated across the resistor and concluded that the inductor would have to be less than 3.3volts. This answer choice was wrong however. The answer choices are 6.7V, 2.5V, 3.4V, 10V, and 7.6V. 10V...

Thanks for the response. Unfortunately, I do not know how to work with complex numbers. Do you have any other suggestions?

Homework Statement An oscillator producing 10 volts (rms) at 200 rad/s is connected in series with a 50 Ω resistor, a 400 mH inductor, and a 200 μF capacitor. The rms voltage (in volts) across the inductor is Homework Equations Xc=1/wC, Xl=wL, Vrms= Irms(Z), Z=(R^2 +(Xl-Xc)^2)^(1/2)...

Homework Statement Would it be possible to do a double-slit experiment for water waves? Can you observe wave interference in the turtle pond on campus? Homework Equations The Attempt at a Solution I feel that since water waves are in fact waves, they can no doubt interfere with...

Homework Statement Do magnetic fields occupy space? Homework Equations The Attempt at a Solution I think the answer is no but I am having a terribly difficult time explaining why. All I have seen online is that like light, the magnetic field is composed of non-massive particles...

Yes. The question I gave you was a copy paste from the document.

Sorry about that. Q=CV, C=(epsilon)A/d, V=Ed/ By substituting these last 2 equations into the first, the result is Q=(epsilon)A(E)-->8.85e-12(0.2)(2e6)= 3.54e-6. However, this is half of the correct answer. What am I doing wrong?

Homework Statement A parallel-plate capacitor has a plate area of 0.2 m2 and a plate separation of 0.1 mm. To obtain an electric field of 2.0 × 10^6 V/m between the plates, the magnitude of the charge on each plate should be Homework Equations Q=epsilon(E)(A) The Attempt at a...

Homework Statement See the attached image. Homework Equations V=IR, Kirchoff's Law The Attempt at a Solution The voltage drop across resistors in parallel are equivalent due to Kirchoffs law (at least I think so?), so V=R(eq,top)I(top)=R(eq,bottom)I(bottom)-->...

Homework Statement See attached image. Homework Equations V=IR, Kirchoff's Law The Attempt at a Solution I thought that since the resistors are in parallel, the voltage drop across each one would be equivalent, so V=I1(14)=I2(38)=I3(7)=I4(Rx). From here I became stuck. Please help!