Recent content by Ragnar1995
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Flow Rate in Horizontal Rectangular Channel: Solve Now
Homework Statement In a horizontal rectangular open channel 20 m wide the water depth is 9 m. When a smooth hump 1.5 m high is introduced in the channel floor, a drop of 1 m is produced in the water surface. What is the flow rate, neglecting energy losses? It is proposed to place a pier at the...- Ragnar1995
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- Flow Fluid Fluid flow
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Im after watching a video on it, but i don't understand why P2A2 and the force is negative, the right hand side i understand.- Ragnar1995
- Post #16
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Why is P2A2 and Force negative?- Ragnar1995
- Post #14
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Turns out i need to use momentum balance to solve it thanks to Chestermiller :) Thanks for your help !- Ragnar1995
- Post #12
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
That gives the correct answer, thanks a lot ! il need to go over momentum balance to understand it now :)- Ragnar1995
- Post #11
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
could you show working please ?- Ragnar1995
- Post #8
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Ye i understand what you mean, might start doing it :) I used the area of the nozzle, 0.0314m^2, i also tried the area of the pipeline but it didnt work either.- Ragnar1995
- Post #6
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Any idea how to do it?- Ragnar1995
- Post #4
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
ok firstly i used velocity=flow rate/area to calculate the v1 and v2. v1=9.20m/s and v2 = 20.69m/s P1/ρg + V12/2g + z1 = P2/ρg + V22/2g + z2 P1/9810 + 9.2^2/2*9.81 = 1.01x10^5/9810 + 20.69^2/2x9.81 P1=2.73x10^5 Then i subbed into the equation F=PA to give 8567.69 N- Ragnar1995
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Force Exerted by Water at Nozzle
Homework Statement A nozzle at the end of a horizontal pipeline discharges water into the atmosphere. The rate of discharge is 0.65 m3 /s. The pipeline has a constant diameter of 0.3 m and the downstream end of the nozzle has a diameter of 0.2 m. Calculate the force exerted by the water on the...- Ragnar1995
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- Force Nozzle Water
- Replies: 21
- Forum: Introductory Physics Homework Help