thank you :smile:
i also figured out that the equation for
initial velocity{v0} = R{range of projectile}/ square root of (2yo/g)
and i also overlooked that the angle was also given in the problem which is 0 degrees:rolleyes:
steps:
solve for t:
y = yo + vy t - (1/2)gt^2
instead of...
Initial Velocity of Projectile
given:
- let theta be: B
-equation for:
(E1)horizontal component is x = vxt; where vx= v0cosB
(E2)vertical component is y= y0 +vyt - (1/2)gt(squared); where vy = v0sinB
using these components an equation of initial velocity{v0} =...