Recent content by raindrop09

thank you :smile: i also figured out that the equation for initial velocity{v0} = R{range of projectile}/ square root of (2yo/g) and i also overlooked that the angle was also given in the problem which is 0 degrees:rolleyes: steps: solve for t: y = yo + vy t - (1/2)gt^2 instead of...

Initial Velocity of Projectile given: - let theta be: B -equation for: (E1)horizontal component is x = vxt; where vx= v0cosB (E2)vertical component is y= y0 +vyt - (1/2)gt(squared); where vy = v0sinB using these components an equation of initial velocity{v0} =...