Recent content by Rey4312

solved it... thanks for the help

i figured it out... i ended up having to do m2a+m1a

W for the hanging box is 16.66 and W for box 2(m2) is 21.56... Where do i go from there, because that doesn't give me acceleration...

But if i do that the acceleration = 0 and so it makes all the forces 0... right??or am i missing something and it should be gravity?

Sorry didn't see that the first time.. so it would be net force?

the component parallel would be tension.

directly down parallel with the slope

W= mg (mass*gravity)

w=mg, tension?, or would it be the normal force (though i thought that was perpendicular)

oh okay... the only force that i can think of would be friction, at least that is parallel

I was given it... Could you use the trig function tangent? so then your equations would be: w tan(37)=3 a and w tan(45)=.86 a but then you're only left with acceleration, and there's two different ones.

Homework Statement In the figure below, assume that the slope is frictionless and that the two blocks are connected by a massless cord. Assume the following: θ1 = 37° θ2 = 45° m1=3kg m2=0.86kg. What is the tension in the cord?. Homework Equations F=ma , w=mg, trig The...

Homework Statement There are three blocks connected by strings as shown in the figure. Each block has the mass as following mass, m1=0.8kg m2=2.2kg m3=1.7kg Assuming there is no friction, Homework Equations F=MA The Attempt at a Solution In my FBD of the hanging box...