Recent content by Rhdjfgjgj

The end result of improper integral itself gave the hint that I had to break the limit. But where, I would be glad if you could help me out on this

I completed the square 1+t+t^2 =1+2(1/2)t+(1/2)^2+3/4

Im sorry about the picture.

No there's this formula that goes like Sin2x=2tanx/(1+tan^2x) It's a standard trigonometric formula.

Read it yah we are done

Thanks and even on reading other materials, I found out that since net charge inside the dielectric is zero, it's virtually an empty space between the induced charges

and in this post i do understand what you meant by saying that but i m writing the value of E ind independently with induced charges

sir all of that is fine my main issue here is that i m confused of the field by the induced charges. . I would have written that expression Eind =qi/(ae), if there were no dielectric. but since i m finding field for a point inside dielectric i think it must be written like qi/(kae) (e...

With the difference in tone zones, it is becoming difficult to interact. . So I would appreciate it if you could just explain it for me

Nooo. Eind is the field due to induced charges on the dielectric surface. Einside is my field. I know see

It must be qi/(Ake) (e : permittivity of free space) I m sorry, im not able to use the mathematical conventions so I'm typing them down.

The value of Eind . Observe ##~E_{\text{ind}} ## is the field due to induced charges at a point inside the dielectric. As taught in electrostatics, permittivity of free space(epsilon not) must be multiplied by the dielectric constant. That's why they must be a k multiplied in the denominator...

my sir gave us the above question as homeork,our task to derive why it happens so I couldnt get it right. So today he gave the answer to it. we were also a..sked to find the induced charges on the dielectric surface. . E ext : electric field between capacitor plates when no dielectric was put E...

Well, in that case vo(object velocity) should have been -4voi