Recent content by rich86

thanks, that helps a lot... ..but makes my project harder in finding the right direction for the escape velocity!

hi, i have been looking for a while but stillnot managed to find a vector equation for the Escape Velocity. i know the escape velocity is: v=sqrt(2GM/r) i would like a vector form to extend a program i am making for a three body gravitational problem many thanks richard

ok sorry i was being really stupid the 1.77MeV comes from 2MeV-0.23MeV. many thanks for your help.

ok so plugging in theta=180 and E=2MeV to http://nucleus.wpi.edu/Reactor/pics/rscineq2.jpg gives E' as .23MeV as is shows in the diagram. http://nucleus.wpi.edu/Reactor/pics/rscin3.jpg But then theta=0 (ie gamma ray has most energy and electron is not scattered) E'=2MeV. this is not what is...

According to these equations the Compton edge should be the same energy as the photo-peak, as when theta=0 the equation is just 662keV/1. i don't understand how it is possible to calculate the Compton edge, with these equations.

I am trying to calculate the energy at which the Compton edge occurs for a sample of Cs137 using a NaI(Tl) scintillator. I know the original energy of the gamma ray was 661.6keV. and that for the Compton edge the angle between the electron and the line of incident must be 0degrees (for max...