Recent content by roadrally2

no, rt(x) is the 'top' draw a picture of rt(x) and 2x^2-1 you can see easily which one is the 'top'

Homework Statement let r(t) (a<t<b) be a smooth vector valued function. suppose that the nonzero vector n is perpendicular to r'(t) for all values of t. Prove that the curve with parametrization r(t) lies in a plane Homework Equations The Attempt at a Solution i know this has...