Prove that a curve lies in a plane

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SUMMARY

The discussion centers on proving that a smooth vector-valued function r(t) lies in a plane when a nonzero vector n is perpendicular to its derivative r'(t) for all t in the interval (a, b). The key insight is that the cross product n x r'(t) generates a vector that defines the plane containing r(t). Since r'(t) has no component pointing away from the plane, the tangent vectors at any three distinct times t are coplanar, confirming that the curve remains within the defined plane.

PREREQUISITES
  • Understanding of vector calculus, specifically smooth vector-valued functions.
  • Knowledge of the properties of derivatives and tangent vectors.
  • Familiarity with the cross product and its geometric interpretation.
  • Concept of coplanarity in three-dimensional space.
NEXT STEPS
  • Study the properties of the cross product in vector calculus.
  • Learn about the implications of tangent vectors and their relationships to curves.
  • Explore the concept of coplanarity and its applications in geometry.
  • Investigate the role of normal vectors in defining planes in three-dimensional space.
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Students of vector calculus, mathematicians, and anyone interested in understanding the geometric properties of curves in three-dimensional space.

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Homework Statement



let r(t) (a<t<b) be a smooth vector valued function. suppose that the nonzero vector n is perpendicular to r'(t) for all values of t. Prove that the curve with parametrization r(t) lies in a plane

Homework Equations




The Attempt at a Solution



i know this has somethign to do with cross product. infact i know that the cross product of n x r'(t) will give me a third vector which will define the plane which r(t) lies in, but I don't know how to show a proof of this.

Thanks for your help or advice
 
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r(t) is the curve, r'(t) is how the curve moves, so, if r'(t) is penpendicular to n where n is some normal vector to a plane, then that means no component of the r'(t) vector is pointing "away" from the plane.

so, if it doesn't move off the plane means that tangent vectors at any three distinct time t's to the curve r(t) are coplanar.
 

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