(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

let r(t) (a<t<b) be a smooth vector valued function. suppose that the nonzero vector n is perpendicular to r'(t) for all values of t. Prove that the curve with parametrization r(t) lies in a plane

2. Relevant equations

3. The attempt at a solution

i know this has somethign to do with cross product. infact i know that the cross product of n x r'(t) will give me a third vector which will define the plane which r(t) lies in, but I dont know how to show a proof of this.

Thanks for your help or advice

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# Homework Help: Prove that a curve lies in a plane

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