Recent content by Robert J. Grave

After the time deration of the accelleration periods, there is no time dillation since linier motion does not produce durrable time dillation just as in SR. So it seems that the accelleration values must be required to determine the actual time difference the twins will experiance. -Robert.

It's not that accelleration does not occur, it's that it's value is not important but the fact that it, the accelleration, results in the creation of another inertial frame and a time differance. So do you need the actual rate of acceleration to find the time difference value? -Robert.

Doc Al I approached the problem as two forces applied to block of mass M. 1. gravity produces a force down the incline = to sin30xMg = .5Mg 2. mass 2M, through the 2 to 1 pulley system, applies a force to M in the opposite direction = to 2Mg/2 = Mg 3. the result of these two forces is...

If time is flat in QM, how do we explane time dilation in relativity, an observed occurrence? -Robert.

Mass/energy and space/time together is the universe. They cannot exist separately. The shape of space/time is related to the mass in it. All aspects of space/time are altered by this shape change. Three spatial and one time dimension. This effect is the gravitational effect. The more accute the...

F(x), I can't get a=g/3. Could you show your final math that got a=g/3? Thanks. -Robert.

I like Hawking statement. The energy of the expansion of the universe was barrowed from gravity which will be given back durring the collapse of the universe. The expansion energy is positive and the energy of gravity is negative. The total of all energy in the universe is equal to zero. -Robert

The change in direction and the resulting accelleration is relative to the mass of the entire universe not just between the twins so which one ages is the one accelerating. If two cars are traveling side by side and one steps on the gas and speeds away it's that cars occupants that feel the...

The ice is already touching the tray. As it melts the melting water in contact with the tray will cling to the tray. Remember the water will occupy a smaller volumn than the ice cube did. surface tension would tend to pull it away from the tray into a drop or sphere shape. The result, I think...

This is a tough one. Assuming that all of the melting energy is used and stored in the melted water. Surface tension will probably leave the water touching the tray since 1/6 th of it was already in contact with the tray at the start. Now it probably will take the shape of a drop of water...

You give a spacific value for acceleration so you must have a value for M and 2M. Do you mean that 2M is twice M, 2M=2xM? What is the values of M and 2M? -Robert

One odd thing reg. DM. Why is it not found on Earth or the moon? I assume it may not be in the solar system. -Robert

The inclined plane gives M a force along the inclined plane = to Mxgxsin(30) or F= .5xMxg. Pulley A is fixed and pulley B is movable. The pulley system gives a 2 to 1 advantage to M so that the opposing force from 2M is = to 2F= .5x2Mxg. The net force is the difference of the two. acc=...

Where does the increase in energy to melt the ice come from? How does it disperse? Is there an atmosphper present? The water is a ball because of surface twension? That surface tension will also cause the water to cling to the tray too won't it? What about the gravitational attraction pan to...

The experiment from John Gribbin's book, page 5, goes like this. There are TWO slits open at all times. Photons are put through the experiment one at a time. After millions of photons have passed through and accumulated on a photo plate an intereferance pattern forms. This was actually done in...