Roberto Pavani's latest activity

Unfortunately, as I've already pointed out, it's often confused with modeling antiparticles as particles with arrows in Feynman diagrams...

I'm not sure I fully understand the one-electron hypothesis, so please correct me if I'm wrong. What I understand is: Under CPT, at...

Any relativistic quantum field theory needs an underlying globally hyperbolic manifold.

Thank you for taking the time to post a detailed reply. It's always good to have a sober, grounding antidote against AI's tendency to...

You're right! f(n) = n·ln(n)·ln(ln(n))·... works too, for any finite number of iterated logs (integral test: each step gives the next...

From practical experience (choir singing, reading music, and knowing people who sing "out of tune"): Pitch control is primarily...

The transfer function H(s) of this network is well-defined and unambiguous. The "no solution" issue lives entirely in the definition of...

@Dale As I suggested earlier, this thread would be better suited for the Electrical Engineering forum section. The reason is simple...

Step generators do not exist. Wires without impedance (neither R nor L) do not exist. The circuit as stated is electrically invalid: V-C...

As an undergraduate answer, this is one of the best answer (more than sufficient). The implicit prerequisite is that you're working in...

Very similar to post #6. $$ a^0=a^{x-x}=\frac{a^x}{a^x}=1 $$

##a^0=a^1a^{-1}=a\frac{1}{a}=1##

My 2 cents: For the general case where the rope length grows as ##L(t) = L_0 \cdot a(t)##, the ant reaches the end if and only if...

V(C2) = 1/2 V(V1) in t=0+ 1) Step generator is ideal 2) Analytical continuation: lim R2->0 -> V(C2) = 1/2 V(V1) R2 is the one in...

A cheap thermal camera (~€150, clips onto a smartphone) would be a nice modern upgrade to this experiment. Instead of two point...