Robeurer's latest activity

My dad was a pistol, that makes me a son of a gun...

And if you want inline fractions to look bigger, use \dfrac instead of \frac Inline with \frac ##a=\frac{F}{m}## is the acceleration...

Check your working. I get ##T=\frac{-5a+300}{4}##. I don't know if this is the only mistake. As @kuruman says, the preferred approach...

Why? The original statement of the problem is To @Robeurer : I recommend that you solve the problem algebraically instead of...

Think of it this way. The hanging mass has downward linear acceleration of magnitude ##a_{\text{hanging mass}}.## Every point on the...

So the equation for the torque will be $$TR-f_fR-f_wR=I\alpha$$ $$T-f_f-f_w = \frac{1}{2}Ma$$ From there we can obtain two equations...

If the cylinder's acceleration is 0, then the equation for both forces on x and y plane should be like this $$T+f_f-N_w = 0$$...

Read what I wrote exactly:

The center of mass of the cylinder is not accelerating, so all the forces on the cylinder must cancel. That would be static friction...

@Robeurer, in addition to what's already been said: Is the rope wound around the cylinder (like a yo-yo) or is the left end of the rope...

The horizontal forces on it are the friction from the floor, the pull of the rope, and the normal force from the wall. The first two...

After re-read the question, the rope is wound around it.

I'm not sure either, but maybe it's wound around the cylinder.

How come the cylinder is not accelerating? I thought that it will also accelerate just like the falling mass like in the Atwood's...

@Steve4Physics @ibrkic0 I'm really really sorry that it looks like there's a mistake. The question asks about the acceleration of the...