Recent content by Rock00

Thank you! Just out of curiousity, is the coefficient we get for V' the answer to X'. I got V' = (.017) (sqrt (k)/sqrt(m)) and when I plug in for v'^2= (k/m)(x')^2 I get x=.017. Is it suppose to be that way, I am really confused. Well if it is thank you Marlon and everyone else who has...

trust me I have been looking at it for days, but I can't seem to get an answer. I literally have five pages of work and to no avail. I need a solution. As always, appreciated.

Thank you marlon. I still do not know what to do after I get the Y. I got Y=301686.116/(k*m) Help would be appreciated.

Help Can you give me advice as to how I would find Force constant, the potential energy and the displacement. Thank you

The work I have provided is what I knew. I didn't know what to do. By the way can you help me out with the Conservation of energy question. A physics guru by the name of Marlon says y = \frac{gt^2}{2}. How did he get that. Help would be appreciated.

does anyone know how marlon got y = \frac{gt^2}{2} any help appreciated

Where are you getting the 2 from and what is the t for? is 2 part of the equation and t is for time and if t is time then how would you get time or 1.93 m. Thank you

Please show work Hi, do you think you can show me the process of how you started the problem. I would greatly appreciate it. Thanks

A 7.94 kg stone is resting on a spring. The spring is compressed 10.2 cm by the stone. (a) Calculate the force constant of the spring. (b) The stone is pushed down an additional 28.6 cm and released. How much potential energy is stored in the spring just before the stone is released? (c)...

Clear diagram of previous post! Attached is a clearer diagram of the previous posted diagram! :smile:

Question is: ------------ Two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring loaded gun that is mounted on a table. The target box is 2.20 m horizontallyl from the edge of the table. Bobby compresses the spring 1.10 cm, but the...

Two trains, each having a speed of 34 km/h, are headed at each other on the same track. A bird that can fly 58 km/h flies off the front of one train when they are 102 km apart and heads directly for the other train. On reaching the other train it flies directly back to the first train, and so...