A 7.94 kg stone is resting on a spring. The spring is compressed 10.2 cm by the stone.(adsbygoogle = window.adsbygoogle || []).push({});

(a) Calculate the force constant of the spring.

(b) The stone is pushed down an additional 28.6 cm and released. How much potential energy is stored in the spring just before the stone is released?

(c) How high above this new (lowest) position will the stone rise?

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Answer:

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Diagram:

(rock on top)

______

(

)

( k ==> Spring

)

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(I have attached a better diagram of the above image)

Given

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m= 7.94 kg

spring compressed = .102m

I know the total change in energy is 0, so how do I start on the problem?

What formulas should I (can you please list it out)?

Any help would be appreciate it!!!

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# Homework Help: Energy Conservation - Rock compression

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