I think i may have figured out B) :)
The force required to accelerate the loaded lorry
A= (v2-u2) / 2s
A= (13.41^2 - 0) / 2(80)
A= 179.83 / 160
A= 1.12m/s2
F=ma
F= 3100 x 1.12
F= 3472N
The retardant force. (the deceleration was given in the question)
F=ma
F= 3100 x -1.5
F= -4650N
now the...
thats the problem i face. it says in the background info that:
The lorry is then loaded with 800 kg of building materials that need to be transported over a total distance of 0.6 km. After loading, the lorry accelerates over a distance of 80m to attain a velocity of 30mph again.
that is all the...
For the force Required for the unloaded lorry:
A=V/T
A= ((30 x 1.6093)x1000) / 3600
A= 13.41 / 10
A= 1.341 m/s2
F=ma
F= 2300 x 1.341
F= 3084.3 N
The retarding force
A= (v2-u2) / 2s
A= (0 - 13.41^2) / 2(70)
A= 179.83 / 140
A= - 1.28m/s2
F=ma
F= 2300 x -1.28
F= -2944N
Time :
the first...
1. Homework Statement
Ok I have been given an assignment and asked to answer questions about a lorry loaded and unloaded. the Text is as follows:
An unloaded lorry of mass M kg accelerates from rest and reaches a velocity of 30mph in 10 seconds. It then travels at constant velocity for half a...
hey i edited the original message. i think i have got the full way to B) correctly. I need B to continue though, so you can see my de lima. I usually know what I am talking about when it comes to physics but this has really stumped me! any help is a positive result :)
Also does anyone know the...
Homework Statement
Ok I have been given an assignment and asked to answer questions about a lorry loaded and unloaded. the Text is as follows:
An unloaded lorry of mass M kg accelerates from rest and reaches a velocity of 30mph in 10 seconds. It then travels at constant velocity for half a...