How Does Mass Affect Acceleration and Deceleration in a Lorry?

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Homework Help Overview

The discussion revolves around a physics assignment concerning the effects of mass on the acceleration and deceleration of a lorry, both when unloaded and loaded with additional weight. The problem includes specific parameters such as mass, velocity, and distance, and poses several questions regarding forces, time, distance, and momentum changes.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply kinematic equations to determine forces and distances but expresses uncertainty about their calculations. Some participants question the completeness of the problem statement and the relevance of certain details, such as the total distance of 0.6 km.

Discussion Status

Participants are actively seeking clarification on the problem's details and the original poster's understanding of the physics concepts involved. There is a focus on ensuring all necessary information is included to facilitate further discussion.

Contextual Notes

There are indications of missing information regarding the unloaded lorry's acceleration and specific questions posed in the assignment. The original poster also references an unrelated physics concept, which may indicate confusion or a broader context of inquiry.

RoryOBigtool
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Homework Statement


Ok I have been given an assignment and asked to answer questions about a lorry loaded and unloaded. the Text is as follows:
An unloaded lorry of mass M kg accelerates from rest and reaches a velocity of 30mph in 10 seconds. It then travels at constant velocity for half a minute before the driver applies the brakes and brings the vehicle to rest over a distance of D m.
The lorry is then loaded with 800 kg of building materials that need to be transported over a total distance of 0.6 km. After loading, the lorry accelerates over a distance of 80m to attain a velocity of 30mph again. The vehicle subsequently maintains constant velocity before decelerating to rest at a rate of R m/s2.

M=2300KG D = 70m R = 1.5m/s^2

Homework Equations


The questions exactly
Find for the unloaded lorry:

i) the force required to accelerate the vehicle, and the retarding force necessary to bring it to rest;
ii) the total time and the total distance traveled during this period.

Find for the loaded lorry :

i) the force required to accelerate the vehicle and the retarding force necessary to bring it
to rest;

ii) the total time taken during this period and the distance traveled at constant velocity.

c) Calculate the % change in the momentum of the lorry from loaded to unloaded, whilst traveling at the specified constant velocities.

d) Draw the ‘velocity-time’ graph of the motion of the lorry in its unloaded and loaded states, indicating clearly salient points and values.

The Attempt at a Solution


I tried using V^2 = U^2 +2as , V=S/t and general thinking but I am 100% sure that I am incorect. i got answers like 0.65 m/s^2 which seemed possible but it is half the acceleration than when the lorry was unloaded, i think half is too little if only 800KG was added. i also got stupid answers like 15.67 m/s^2

can some one help me
 
Last edited:
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Read your own post again and you'll see why I can't understand it at all. What information is provided about the unloaded lorry? What's the actual question? Why does the 0.6 km matter?
 
I believe you left out some info regarding the unloaded lorry, like its acceleration, speed, etc. And you left out the question as well. Please re-write this problem in its entirety.
 
hey i edited the original message. i think i have got the full way to B) correctly. I need B to continue though, so you can see my de lima. I usually know what I am talking about when it comes to physics but this has really stumped me! any help is a positive result :)

Also does anyone know the value of e in the equation of electric field strength ( E = 1 / 4(pie) eo er x Q1Q2/r^2 )?
 
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