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Max Speed of Car: 80m Track & .40 Coeff of Friction
F stands for centripetal force, M stands for mass, and a stands for centripetal acceleration. This is the formula we used in class: F=ma Is this the equation of centripetal force or just Newton's 2nd Law for Circular Motion?- RoyG
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- Forum: Introductory Physics Homework Help
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Max Speed of Car: 80m Track & .40 Coeff of Friction
normal force is the mass times gravity?- RoyG
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- Forum: Introductory Physics Homework Help
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Max Speed of Car: 80m Track & .40 Coeff of Friction
okay so I did (.40)(m)(9.8)=m(V^2/80) which comes to be 3.92m=m(V^2/80) and then I tried substituting V^2 with 160pi/time because of 2(pi)(r) how do I work with the two variables?- RoyG
- Post #4
- Forum: Introductory Physics Homework Help
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Max Speed of Car: 80m Track & .40 Coeff of Friction
Homework Statement "what is the maximum speed at which a car can safely travel if the radius of the track is 80.0 m and the coefficient of friction is .40" friction is providing the force and the track is flat and circular. Homework Equations the equations that we've been using in class...- RoyG
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- Car Maximum Speed
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- Forum: Introductory Physics Homework Help