would it be 25.8m/s / .56s (46.07142857) for the acceleration. and I now that the second law is Fnet=Ma...OO, so it is 46.07142857*930.1=42851.03571 N?
I changed 36 miles per hour to .01 miles per second which converts to 16.09344 meters per second. I divided that by 1.9 which equals 8.470231579 as the average acceleration. Then for the second part 8.470231579*52 = 440.4520421 N as the force exerted. I'm pretty sure that is what I did.
A dragster and a driver together have mas 930.1 kg. the dragster, starting from rest, attains a speed of 25.8 m/s in .56 s. Find the average accel. of the dragster during ths time interval. What is the size of the average force on the dragster during this time interval? Answer in units of N...
Suzie (of mass 52kg) is roller blading down the sidewalk going 36 mph. She notices a group of workers down the walkway who have unexpectedly blocked her path, and she makes a quick stop in 1.9 seconds. What is Suzies average acceleration? Answer in m/s^2. What force was exerted to stop Suzie...