Calculating Average Acceleration and Force of Dragster and Driver

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rr92890
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A dragster and a driver together have mas 930.1 kg. the dragster, starting from rest, attains a speed of 25.8 m/s in .56 s. Find the average accel. of the dragster during ths time interval. What is the size of the average force on the dragster during this time interval? Answer in units of N.
The driver has a mass of 74.9 kg. What horizontal force does the seat exert on the driver.

I'm not even sure where to start.
 
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would it be 25.8m/s / .56s (46.07142857) for the acceleration. and I now that the second law is Fnet=Ma...OO, so it is 46.07142857*930.1=42851.03571 N?
 
not *930.1 , *74.9.
Because you're talking about the force exerting on the driver,not both of them.
 
Von said:
not *930.1 , *74.9.
Because you're talking about the force exerting on the driver,not both of them.

Erm...

rr92890 said:
A dragster and a driver together have mas 930.1 kg. the dragster, starting from rest, attains a speed of 25.8 m/s in .56 s. Find the average accel. of the dragster during ths time interval. What is the size of the average force on the dragster during this time interval? Answer in units of N.
The driver has a mass of 74.9 kg. What horizontal force does the seat exert on the driver.
 
Hootenanny said:
Erm...

?

(I wanted to post just the '?', but evidently it found the post too short and didn't accept! But Hootenanny's post is considered to be a complete thesis?
 
Von said:
not *930.1 , *74.9.
Because you're talking about the force exerting on the driver,not both of them.

He also has to find the force on just the dragster. So, *(930.1 - 74.9).

Do you understand the Erm... now?
 
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Didn't see that! o(∩_∩)o...