Recent content by rssvn
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How to find out the sin value from cos
i need the square root for sin(x)2=4/9, i may have overestimated the question at first- rssvn
- Post #4
- Forum: Precalculus Mathematics Homework Help
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How to find out the sin value from cos
First off sorry if something doesn't make sense, english is not my native language. I know i should start with sin2 α + cos2 = 1, but ant really continue from it. i am being confused by cos α = √5/3 since i know it isn't found in normal trig tables. So my problem is how to find out values of...- rssvn
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- Cos Sin Value
- Replies: 9
- Forum: Precalculus Mathematics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Good tips, i will definitely remember them. Thank you for all the help, I've learned a lot :)- rssvn
- Post #20
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Would this be better?- rssvn
- Post #18
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Oh seems that i forgot to insert the right values, it was meant to be: θ₁=sin-1((1.62sin(37◦))/1.4) and the answer for β would be 44º (i think significant figures mean the answers accuracy? so to say) Would the diagram in the attached photo be sufficient?- rssvn
- Post #16
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
I'm trying to solve the β angle, n₁=1.4, n₂=1.62, θ₂=37◦, θ₁=? n₁sinθ₁ = n₂sinθ₂ sinθ₁=(n₂sinθ₂)/n₁ θ₁=sin-1((n₂sinθ₂)/n₁) θ₁=sin-1((1.4sin(37◦))/1.62) θ₁=44.14◦- rssvn
- Post #14
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Is the answer then (1.62sin(37))/1.4 -> arcsin(ans)- rssvn
- Post #12
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Ooh, so because the flintglass is submerged, the laser must have been traveling in the oil already before it hit the flintglass, and since the b angle is angle it hits the flintglass it must come out in the same angle too?- rssvn
- Post #9
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
I don't quite understand why i need the b angle to answer the question- rssvn
- Post #7
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
oops, my bad, edited it to include the question :D- rssvn
- Post #3
- Forum: Introductory Physics Homework Help
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Refraction of light question -- Flintglass submerged in oil
Hello, hopefully the question made sense, it was hard to translate. i attached a photo about the question. I started with n1=1.4, sinΘ1=37◦ and n2=1.62 1.4(sin(37◦))=1.62sinΘ2 1.4(sin(37◦))/1.62=sinΘ2 arcsin(0.52)=31.34◦ Is it calculated correctly?- rssvn
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- Light Oil Refraction Refraction angle Refraction of light Submerged
- Replies: 19
- Forum: Introductory Physics Homework Help
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Car passing a truck — calculating the relative motions
Sorry for taking so long to answer, i understand now, (25m/s)t=37.5m+(18m/s)t -> 25t-18t=37.5m -> 7t=37.5m -> 5.36. Thank you @PeroK and @haruspex for bearing with me, i do appreciate it :)- rssvn
- Post #35
- Forum: Introductory Physics Homework Help
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Car passing a truck — calculating the relative motions
I'm sorry if I am not understanding, but how can i figure out the t if not by trial and error- rssvn
- Post #32
- Forum: Introductory Physics Homework Help
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Car passing a truck — calculating the relative motions
What equation should i use if i don't use the trial and error, isn't the equation you gave Xcar = Xtruck basically using trial and error?- rssvn
- Post #30
- Forum: Introductory Physics Homework Help
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Car passing a truck — calculating the relative motions
Ah, youre right, maybe I'm trying to rush the answer and make silly mistakes like that on the way, t = 5.35s seems to be pretty close, i tried it by trial and error. 5.35s and 133.75m- rssvn
- Post #28
- Forum: Introductory Physics Homework Help