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- Homework Statement:
- A container hold oil with refraction index of 1.4. A flintglass? (maybe a wrong translation) is submerged into the oil, with a incline of a=37◦ flintglass index is 1.62. Laser is shot at the flintglass which then exits into the oil, what is the angle when the laser exits the glass?

- Relevant Equations:
- n1sinΘ1=n2sinΘ2

Hello, hopefully the question made sense, it was hard to translate. i attached a photo about the question.

I started with n1=1.4, sinΘ1=37◦ and n2=1.62

1.4(sin(37◦))=1.62sinΘ2

1.4(sin(37◦))/1.62=sinΘ2

arcsin(0.52)=31.34◦

Is it calculated correctly?

I started with n1=1.4, sinΘ1=37◦ and n2=1.62

1.4(sin(37◦))=1.62sinΘ2

1.4(sin(37◦))/1.62=sinΘ2

arcsin(0.52)=31.34◦

Is it calculated correctly?