Recent content by rwinge

Nevermind! haha I ended up getting it. I was just thinking about the force of friction wrong. Somehow I neglected to include gravity in my first calculation which gave an extremely long distance. thanks for the input guys!

Okay so I think I am heading in the right direction now. IVe got Work = (delta K) + ( delta Uspring) + (delta Ugravity) delta K = (1/2)Mvf^2 - (1/2)Mvi^2 = 20.92 J delta Uspring = (1/2)Kxf^2 - (1/2)Kxi^2 = -15 J delta Ugravity = (1/2)mghf - (1/2)kxf^2 = -12.31 J adding theses...

Homework Statement A 785-gram metal block is placed on a level table that is 1.6 m high. It is connected to a horizontal spring whose force constant is 3000 N/m. The block is pushed against the spring, compressing it by 0.100 m, and released. It slides along the table and goes off of the...