- #1
rwinge
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Homework Statement
A 785-gram metal block is placed on a level table that is 1.6 m high. It is connected to a horizontal spring whose force constant is 3000 N/m. The block is pushed against the spring, compressing it by 0.100 m, and released. It slides along the table and goes off of the edge.
Coefficient of kinetic friction is 0.200 (Uk)
If the speed of the block just before it strikes the ground is 7.3 m/s, what distance did the block slide along the table?
Homework Equations
Work = delta K + delta U
U spring= (1/2)Kx^2
K block = (1/2)mv^2
The Attempt at a Solution
What I can come up with so far is that the potential energy of the spring (U) is equal to the kinetic energy done on the block (K). So in that case I set the two equations equal to each other
(1/2)Kx^2 = (Uk)mg(delta X) and so
15 J = 1.54(delta X)
so delta X = 9.74 m.
This doesn't seem very plausable to me with such a high spring coefficient and neglecting to use the height of the table and final velocity.
Any ideas?