I rearranged the equation s subtracting qVi and KE(f) in that form i end up with 2 unknowns rewritten out :
2.0+-2.0x10^-5(Vi)=1/2(4.0 x 10^-8)v^2+-2.0x10^-5(Vi+3.5x10^5)
if i had Vi this would be easy should i be solving for that somehow ...i really don't get this. The lecture was a pretty...
Homework Statement
A small ball has a mass of mass m 4.0 x 10^-8 kg and a charge of q = -2.0 x 10^-5 C. It enters a box with an initial speed of v0 = 1.0 x 10^4 m/s. The point where the charge leaves the box is at a voltage 350 kV higher than the entry point.
Homework Equations...
oh I forgot to add that the question lists the acceleration which was 1.5m/s/s toward the rod. what it wants me to find is the mass of the balloon using the charges listed and the distance between the two objects and somewhere in there using the acceleration I am just completely stumped on how...
Homework Statement
A rod carrying a charge of 8.0uc held above a balloon carrying a charge of -.70 uc. at a height of 30cm. find the mass of the balloon
Homework Equations
fe= (q1*q2)/r^2[/B]
F=ma
The Attempt at a Solution
I do not want this problem solved for me I am very trapped at...