Recent content by Sam223344
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Graduate Euler's Method With Mass Balance o.d.e's
This is what I have but its the square root of a negative number that is confusing me- Sam223344
- Post #3
- Forum: Differential Equations
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Graduate Euler's Method With Mass Balance o.d.e's
Euler's Method With Mass Balance o.d.es I'm doing a practice paper for a past mathematical modelling exam. I've attached the problem What I'm having trouble with is simplifying the equations and variables into a differential equation that is solvable with Euler's Method. What I have...- Sam223344
- Post #2
- Forum: Differential Equations
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Graduate Euler's Method With Mass Balance o.d.e's
Hi I'm doing a practice paper for a past mathematical modelling exam. I've attached the problem What I'm having trouble with is simplifying the equations and variables into a differential equation that is solvable with Euler's Method. What I have currently is the sqrt(h1-h2) in the...- Sam223344
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- Balance Euler's method Mass Mass balance Method
- Replies: 2
- Forum: Differential Equations
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Undergrad How to Prove the Nth Derivative of f(x)=1/(sqrt(1-4x)) by Induction?
Thanks mate this should help me out a lot. -
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Undergrad How to Prove the Nth Derivative of f(x)=1/(sqrt(1-4x)) by Induction?
I'm still a bit fuzzy on how to go about this induction. Could someone do an example of proving an nth derivative(something of similar difficulty) by induction so I can get a better understanding of my problem. Or even post a link to where i could find some examples. Thanks -
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Trig Geometry Problem: Solving sin(x)=cot(x) in Terms of cos(x)
It might be helpful if i explain why a*h=8^2 for this triangle? h^2=8^2+a^2 8=sqrt(h^2-a^2) 8=sqrt(h^2-(h^2-8^2)) 8=sqrt(8^2) so 8=8 so a*h=8^2 I'm still needing conformation that I solved the correct quadratic- Sam223344
- Post #5
- Forum: Calculus and Beyond Homework Help
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Trig Geometry Problem: Solving sin(x)=cot(x) in Terms of cos(x)
For this triangle a*h=8^2. This can be shown by using a^2+b^2=c^2. To show that sin(x)=cot(x) 'in this case' : By using sin(x)=opp/hyp = 8/h and a*h=*^2. Rearrange for h=8^2/a so sin(x)=8/(8^2/a)=a/8 and cot(x)=adj/opp=a/8 so sin(x)=cot(x) for this case. Yeah the angle is acute(sorry...- Sam223344
- Post #3
- Forum: Calculus and Beyond Homework Help
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Undergrad How to Prove the Nth Derivative of f(x)=1/(sqrt(1-4x)) by Induction?
Hey I have this problem on proof by induction that I'm struggling to do. The problem is to prove the nth derivative of f(x)=1/(sqrt(1-4x)) I have worked out that the nth derivative is f^(n)(x)=(2n)!/n! * (1-4*x)^(-(n+1/2)) But I'm not sure how to go about completing this. My lecturer... -
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Trig Geometry Problem: Solving sin(x)=cot(x) in Terms of cos(x)
Homework Statement A triangle with x as the angle, 'a' as the adjacent, 8 as the opposite side and 'h' as the hypotenuse. An intermediate question was to show that sin(x)=cot(x). Now i have to write 'sin(x)=cot(x)' in terms of cos(x) only and solve the quadratic, stating correct value for...- Sam223344
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- Geometry Trig
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Graduate Limit of a recursively defined sequence
The problem is: a(n+1) = ( a(n)^2 +16) / ( 2a(n) + 6) converges to the limit:...? for n>=1 and a(1) = -10 Also note (n+1) and (n) are subscripts Also another question..: If f(x) is a function that is 8 times continuously differentiable such that the coefficient of x^5 in its 8th... -
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Undergrad Certain force to break surface tenson of Jelly
Can you explain why that gives the amount of weight the jelly can hold? It doesn't seem reasonable when I'm sure the same weight would break the surface of the jelly whether it was a 20cm cube or 100m cube. I'm thinking it has something to do with the pressure that the structure exerts on... -
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Undergrad Certain force to break surface tenson of Jelly
I am designing a structure that can rest upon jelly. I know how to determine the surface tension of the jelly in N/m. I can convert this to dynes/cm, J/m^2 etc but that is'nt the problem. I need to figure out the maximum weight of the structure so that its force on the jelly does not break the...