Recent content by Sanchayan Dutta

Sorry.I meant no force accelerates the smaller block right.Of course tension pulls the bigger block.

I don't think anything accelerates B rightwards.I guess I got your point!

Well that means they are not in contact.But it is difficult to visualize such a thing.Can you visualize that happening?

Truly speaking I'm confused by the fact that it is negative...Can you provide an explanation?

Because the pulley moves when the bigger block moves right.In turn the amount of string (horizontal) released moves to vertical position and the smaller block moves further down.Now since the released horizontal part of string becomes vertical naturally the smaller block will keep touching the...

Because the blocks are touching...

Homework Statement 2. The attempt at a solution Let rightward acceleration of the block (A+B) be $$a$$. Let downward acceleration of block (A) be $$a'$$ down. For block A: $$mg-T=ma'$$ $$N+ma=0$$ For block B: $$T+N=Ma$$ On solving $$N=-\dfrac{m^2g}{M+2m}$$ by taking $$a=a'$$.But...

Determine the maximum ratio $$h/b$$ for which the homogenous block will slide without toppling under the action of force F.The coefficient of static friction between the block and the incline is $$\mu_s$$. I have a doubt.About which point should the rotational equilibrium be applied?Should it...

So should I use that rate of diffusion is directly proportional to pressure?

Homework Statement The pressure in a bulb dropped from 2000 to 1500 mm of mercury in 50 minutes when the contained oxygen leaked through a small hole. The bulb was then evacuated. A mixture of oxygen and another gas of molecular weight 72 in the molar ratio of 1 : 1 at a total pressure of 6000...

Oh that's my mistake.So in the second equation i should use $$\sqrt{(vcos(\theta)-V)^2+(vsin(\theta))^2}$$ instead of v.Right?

Homework Statement A bead of mass m kept at the top of a smooth hemispherical wedge of mass M and radius R is gently pushed towards right.As a result,the wedge slides due left.Find the magnitude of velocity of bead relative to the wedge. Homework Equations $$MV=m(v\cos(\theta)-V)$$ and...

Nice to meet you.Bye :-)

Alright.Thank You.You are from india?Which university? =) Thanks a lot for your help!

Ok I get that.So should the heat dissipated be 0 after switch is closed?