Recent content by Sanchayan

Thanks a ton for the help @Hesch :-)! Have a good day :-)!Bbye :-)

I'm getting current in cell as (15.46875/6)=2.57 (approx) am I right?

How do i write the 7 th equation involving the battery? @Hesch

@Hesch I got the 6 equations as follows: i2+i6=4*i1 i3+i1=4*i2 i2+i4=4*i3 i3+i5=4*i4 i4+i6=4*i5 i1+i5=4*i6 Then,the solution of these six equations is i1=i2=i3=i4=i5=i6=0 ! All the currents in all loops is coming as 0! What does that mean??

How did you write the equation for the loop involving the cell ?I got the rest of the 6 equations but I guess my cell equation is wrong! @Hesch

I considered a potential for each node and then applied Kirchhoff 's current law at each junction I got about 10 equations with 10 variables. For example for the node a : (a-11)/6+(a-b)/6+(a-f)/6=0 . [Resistance of each side is 6 ohms] But solving so many equations manually is really tough...

Well ok,but how are you taking the potentials of the nodes? I'm having problem in framing the equations P :-(!

That will make it too complicated.I mean there must be a simpler way! This problem was a 3 min MCQ question in my institute's previous year's question paper!

https://brilliant.org/problems/hexagonal-grid/ I've been pondering on this but not being able to solve.I mean applying Kirchoff's law here is of no use. Any ideas?