Recent content by sargondjani1

I wonder if there is an analytical solution to: b=a*x-θ - x with a>0, b>0, x>0, θ>1

f1(x)>=0 is the same as -f1(x)<=0, so just define f1 appropriately and you get the 'normal' KKT conditions.

hmmm, at first i thought -x^(1/3)+(x-1)^(1/3)+1 worked (i tested only for integers) but f is not monotonically increasing (and f' is not monotically decreasing)... and worse, f even gets negative... but jacquelin your solutions does work perfectly! :-) I am very happy with your quick response...

a bit late, but thanks all for your efforts! Char Limit's thing works perfectly! :-) ... after changing the signs: -x^(1/3)+(x-1)^(1/3)+1

i was shocked at the functions you came up with... then is saw my typo: i would prefer f'(0)=inf (and not f(0)=inf, since i want f(0)=0)

on first reply: i don't see how i can get what i want from x ln(x)... can you eloborate? i mean x ln (x) goes to infinity on second reply: i meant i want f(inf)=1 (monotonically increasing from 0 to inf.), so f'(inf)=0.

f(x) should give the chance of something happening, that's the reason for f(inf)=<1. i used f(x)=1-exp(-a*x) until now, which is ok but f'(0) is not +inf. i would prefer a function with f(0)=+inf. i want the function to be (monotonically) increasing at a decreasing rate (f' decreasing...