Yes you're right sorry. So assuming angular momentum is conserved then from that equation v = 3.616. so for part e to get the angle I used mv^2/rsintheta = mg/costheta to get tantheta = v^2/rg and theta as 69.43°. Does that sound correct?
Homework Statement
A ball of 10kg mass is suspended by a cable that passes through a hole in a floor. The ball rotates in a circular orbit, A, that is in a plane that is 3m below the floor. If the orbit has a radius of 1m, calculate;
a) Tension in the cable
b) speed va of the ball in...