Recent content by Sheldinoh

thanks for all the help

i got it, i think i plugged it into the calculator wrong.

it wants the answer in km/s

ok i just tried it and it said i have the incorrect answer, and it gave me this link http://www-physics.ucsd.edu/students/courses/winter2011/physics2a/Tipler6-2.P.122.pdf do you have any ideas on where i might have messed up?

i got 2.797km/s is that the correct answer?

What's the radial distance to the surface of the Moon? R What's the radial distance to an object at height 3R above the Moon's surface? 4R I see now, i think. so x0=4R, x=R right?

2R, so would i plug 2R in as x and 0 for x0?

Homework Statement For a spherical celestial object of radius R, the acceleration due to gravity g at a distance x from the center of the object is g = (g0)(R^2)/(x^2), where g0 is the acceleration due to gravity at the object's surface and x > R. For the moon, take g0 = 1.63 m/s2 and R =...

would it be: ||3v+w||= ( 16x2+(3vy + wy)2 ) 1/2 . If so, i was kinda under the impression that the professor wanted an numerical answer.

v•w = ||v|| ||w|| cosθ but how would i get to ||3v+w|| from knowing this

im not really sure. is it that the dot product geographically represents the length of one vector over another vector

This question was on my math calc and analytical geometry final and i couldn't figure out how to do this. Its probably something pretty simple but i couldn't figure it out 1. Homework Statement [/b] ||v|| = 1 ||w|| = 2 v•w= (-1/2)||v|| ||w|| ||3v+w|| = ? Thanks in advance for...

Homework Statement Find: ∂f/∂x f(r,θ)=rsin^2(θ), x=rcosθ, y=rsinθ The Attempt at a Solution ∂f/∂r=sin^2θ ∂r/∂x=-cosθ/x ∂f/∂θ=2*r*cosθ*sinθ ∂θ/∂x=-1/sqrt(1-(x^2)/(r^2) ∂f/∂x = -sin^2θcosθ/x^2 + -2*r*cosθ*sinθ/sqrt(1-(x^2)/(r^2) ∂f/∂x = -y-sqrt(x^2+y^2) /...

Thank you so much. You are a life saver.

(M1+M2)a = M1(9.8) + M2(-9.8) (20+5)a = 20(9.8) - 5(9.8) a = 6