Recent content by Shell_E

So I was reading Jackson's discussion on Image charge method of a grounding sphere. He first assumed an image charge q inside Sphere with radius a, so the potential for real change and image charge is . The by set potential equal to 0 at x=a, he solved q' and y' Then he can get potential...

@Jilang @DrClaude Thank you for help! I mislead by the integral sign to think it gained by doing some rearrangement inside the integral. Everything become clear if I do integral by part and use the fact that momentum operator is hermitian. Thanks a lot!

Thank you advance for help! So the problem is find <x> in P space. The solution's logic is use formula: The submit with Then one will get the integral by noticing that , one can replace xeipx/ħ in the integral so that and then after solving the integral one can find the expectation value...