Recent content by shibme
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Solving for I1 and I2: Math Problem with V=IR
ahhh... thank you! Whew... never will I doubt ohms law again...- shibme
- Post #9
- Forum: Electrical Engineering
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Solving for I1 and I2: Math Problem with V=IR
I've scoped through other posts on this forum and I came about this reply by Cliff_J... --------- Ok, in series the voltages would add, in parallel the current will add. Make sure you keep the terms straight, its an important distinction between the two. Parallel is like how a home is...- shibme
- Post #7
- Forum: Electrical Engineering
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Understanding Power Sources: Solving a Circuit Question with V=IR Method
hmm... this question is actually from the book and the answer is in words... it states that the circuit on the right (I2) should be 3x the current on the left (I1), but according to my calculations that is not the case... I can't figure this out mathematically...- shibme
- Post #3
- Forum: Introductory Physics Homework Help
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Solving for I1 and I2: Math Problem with V=IR
ohh... because there's an explanation in the book in words... and I am trying to figure it out mathematically...- shibme
- Post #5
- Forum: Electrical Engineering
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Understanding Power Sources: Solving a Circuit Question with V=IR Method
Homework Statement - see image Homework Equations I am having trouble figuring this out mathematically... I have no idea why but I can't figure it out using V=IR that the circuit on the left has 1/3 the current of the circuit on the right... can anyone please give a mathematical...- shibme
- Thread
- Power Source
- Replies: 2
- Forum: Introductory Physics Homework Help
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Solving for I1 and I2: Math Problem with V=IR
well based on my calculations, it says that the current through RL on the left circuit is greater than the current through RL on right... I know it should be the opposite but I can't show it mathematically... any suggestions? thanks..- shibme
- Post #3
- Forum: Electrical Engineering
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Solving for I1 and I2: Math Problem with V=IR
hi, I am having trouble figuring this out mathematically... I have no idea why but I can't figure it out using V=IR that the circuit on the left has 1/3 the current of the circuit on the right... can anyone please give a mathematical explanation? Left : 3Vb = I1 * RL Right : Vb = I2...- shibme
- Thread
- Replies: 8
- Forum: Electrical Engineering