that's just it, i don't think this is it.
notice that the two charge are in the matter eps_0.
* the other dielectric is only found at (-d/2 < x < d/2 ).
* the two charges are in (x = -d) and (x = +d).
so it seems like the force will be F=qE and E=d/eps_0.
which is exactly like if there...
suppose I have a charge q at (x=-d) and a charge q at (x=+d).
the force between them is q^2/(4*pi*(eps_0)*4*d^2).
now, I insert a dielectric (K) between (-d/2<x<d/2), and try to calculate the force now...
it seems like it would be the same but it sounds strange...
If I use the D field...
Homework Statement
suppose I have a charge q at (x=-d) and a charge q at (x=+d).
the force between them is q^2/(4*pi*(eps_0)*4*d^2).
now, I insert a dielectric (K) between (-d/2<x<d/2), what would be the force between the charges now?
The attempt at a solution
it seems like it...
I have the feeling I got the first two sections wrong...
something about my dealing with the dielectrics.
could you have a look and tell me what you think?
I solved the question, it's not that difficult after all - just a lot of calculations.
solution is attached if you are interested :) if you see an error i would love to know about it..
now - supposed I know the capacitance and the force felt by the upper electrode, and I know all...
Okey so my lecturer had answered to use a small radius spherical electrode instead of a point charge.
actually I'm pretty confused, so I'll try to work on it for a little while and let you know if I made some progress and/or have any questions.
thanks for the help!
shomey
Consider a capacitor which is just like a plate capacitor, but instead of the upper electrode being a plate it is a point charge Q. the lower plate is held at a fixed potential V=0.
how could you calculate the capacitance of the system?
when trying to calculate - it looks like it will be 0...
Homework Statement
I have a capacitor which i just like a plate capacitor, but instead of the upper electrode being a plate it is a point charge Q. the lower plate is held at a fixed potential V=0.
I am supposed to calculate the capacitance of the capacitor.
The Attempt at a...
Hey guys!
I think I've solved it, attached is my solution.
I have some last little points I would love to understand better:
1) why is the field D contant though the capacitor? (I've read it in a notebook but could not understand why this is true - they've claimed it is because of the...