Recent content by SixOnTheBeach

Sorry if I've been repetitive at all, I've just been trying to respond to everyone. So as for the resistance, I don't quite understand what that nice thing is haha. I drew my diagram exactly as you have it! But does the path merely take the short circuit route and through your R1 as it's the...

I would have shown my work, but embarrassingly I don't really have anything to show... All I've done is remove the power sources and the load resistor. And yes, my instructor for this class is really awful, that is why I am struggling so much with these topics as he is pretty useless in helping...

I was adding the 3 resistors in series with the load resistor removed. I assumed this because two of the resistors were in series going into A, and then the third resistor seemed to be in series after B. I have now found out the true resistance is 6kΩ, although I'm not sure why.

Yeah I'm sorry maybe I should've clarified but every example I saw listed across the load as A and B so I assumed it would be obvious, that's on me

So I've been absolutely stumped on this one. I've tried about a million different things but none of them have seemed right. A combination of the odd layout of the circuit, and a combined voltage/current source are making things really complicated for me. I'm somewhat sure the RTh is 15kΩ due to...

Ah, I finally see my mistake! Since the 3mA source was in parallel with the 4kΩ resistor it can be thought of as a 12V source. However, when you bring in the 2kΩ resistor, the 12V voltage will mean a 2mA current (12/6 instead of 12/4). When I use a 2mA current source in my work, it leads to a...

Thank you so much! This was VERY helpful. I totally understand why R3 would be in parallel. I followed this methodology and arrived at 1.85V drop for the 4kΩ, which still varies from the 2V I found in the simulation, but very close! This could possibly just be due to internal errors. I arrived...

I could be wrong on this, but I believe KVL and KCL are allowed! I think he meant more so you can't use source transformations, thevenins, etc, basically anything above the very basics.

Wow, thank you that's very helpful! I may be misunderstanding you, but is IN 3mA, as the only thing pushing current through is the 3mA source? Why does shorting the resistor make the 12V source zero? Can the voltage from it not still travel through the 2k resistor?

That's the description I've been pouring over! But I haven't really had any help from it because the examples they use are so simple! I haven't been able to apply it to the less clear-cut questions. I just figured that the 12V source with the 12kohm resistor would be 1mA, and it would subtract...

So I've just learned Norton's Theorem and I have this problem on my homework assignment that is wrong. I've checked the answer with a circuit simulator(PSPICE) and the simulation said that V0 should be a drop of 2V. However, my simplified circuit shows a voltage drop of 4V. I have been staring...