Recent content by SL_1719

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    Frame of reference, energy and momentum of particle

    Homework Statement In a certain reference frame, a particle with momentum of 4 MeV/c and a total energy of 5 MeV (a) Determine the mass of the particle. (b) What is the total energy of the particle in a reference frame in which its momentum is 4 MeV/c? (c) What is the relative speed of the two...
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    Wire radius from interference fringes

    I am trying to understand what you are saying. The wording to me is a little confusing. So you say that 2d+(1/2λ)=λ, 2λ... Since there are 19 fringes seen, then 2d+(1/2λ)=19λ, as 19 is the n. So 2d=18.5λ if the fringe is right on the edge? I see now, I realized I made a mistake as I did on an...
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    Wire radius from interference fringes

    Well we are told at least 19, in that it could be at the edge, but less than 20, as in the 20th is not there so it being less than but not able to be equal to. So in what ways does the number of fringes per wavelength effect my answer? Because I was going off of what I saw in other posts in...
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    Wire radius from interference fringes

    Well, if that is true to every fringe, how does that effect the end result? Or is it that everything is shifted down one half wavelength?
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    Wire radius from interference fringes

    Homework Statement The diameters of fine fibers can be accurately measured using interference patterns. Two optically flat pieces of glass that each have a length L are arranged with the fiber between them, as shown below. The setup is illuminated by monochromatic light, and the resulting...
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    What is the Phase Difference Between Reflected Waves in a Thin Film of Water?

    Thank you, I completely forgot to factor that in. That was what I was missing and the answer was 3.5 rad.
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    What is the Phase Difference Between Reflected Waves in a Thin Film of Water?

    Homework Statement Light of wavelength 526 nm is incident normally on a film of water 1.0 µm thick. The index of refraction of water is 1.33. (c) What is the phase difference between the wave reflected from the top of the air-water interface and the one reflected from the bottom of the...
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    Force on Earth by the radiation pressure of Sun

    Thank you for welcoming me and thank you for the help, using just pi*r^2 worked. 5.823e8 N is the answer.
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    Force on Earth by the radiation pressure of Sun

    Homework Statement Estimate the force on Earth due to the pressure of the radiation on Earth by the Sun. (At Earth's orbit, the intensity of sunlight is 1.37 kW/m^2.)Homework Equations Radiation Pressure=I/c Pressure=F/A Using SA of earth=510,072,000 km2 The Attempt at a Solution So I have...
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