Recent content by slapshot151
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Glider pulled by suspended mass
anybody?- slapshot151
- Post #2
- Forum: Introductory Physics Homework Help
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Glider pulled by suspended mass
Homework Statement A 1.00-kg glider on a horizontal air track is pulled by a string at an angle θ . The taut string runs over a pulley and is attached to a hanging object of mass 0.500 kg . (a) Show that the speed vx of the glider and the speed vy of the hanging object are related by vx...- slapshot151
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- Mass
- Replies: 3
- Forum: Introductory Physics Homework Help
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Solving for Theta: Homework Help
Thanks a lot! i used this method and got 39.9o and 14.4o double checked and these angles make sense in the original problem. thanks everybody else for contributions bit of a hard problem for first year intro physics huh... if anybody is interested the original problem was An enemy...- slapshot151
- Post #10
- Forum: Precalculus Mathematics Homework Help
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Solving for Theta: Homework Help
[-2500\pmsqrt(25002-4(-1800)(-490))]/2(-1800) x=0.236, 1.153 sorry not so good at writing equations in html... can you do that with the cos\theta in there though? i would understand if it was asin2\theta + bsin\theta + c which would leave you with sin\theta= root 1, root 2 but...- slapshot151
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Solving for Theta: Homework Help
-1800sin2\theta + 2500cos\thetasin\theta -490 = 0 i know how to do that, i just don't know from here how to solve for \theta- slapshot151
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Solving for Theta: Homework Help
Homework Statement i don't think this should be too hard, i just forget how to do it... so i have this problem, and I've got it down to this -490/sin2\theta + 2500cos\theta/sin\theta - 1800 = 0 if anyone can help...- slapshot151
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- Theta
- Replies: 12
- Forum: Precalculus Mathematics Homework Help