Recent content by slaw155
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Net Electric Field Strength at a Point due to a Uniform Electric Field
The answer still came out wrong?- slaw155
- Post #11
- Forum: Introductory Physics Homework Help
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Net Electric Field Strength at a Point due to a Uniform Electric Field
Oh I see. So basically letting A= field due to point charge (which is in y-axis direction) and B = field due to field in x-axis direction, because they are at right angles to each other net electric field at y=0.2m = square root of [ [(9x10^9 x 9.8x10^-9)/(0.2^2)]^2 + (3600^2)]?- slaw155
- Post #9
- Forum: Introductory Physics Homework Help
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Net Electric Field Strength at a Point due to a Uniform Electric Field
Doesn't the point charge give a field in all directions?- slaw155
- Post #7
- Forum: Introductory Physics Homework Help
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Net Electric Field Strength at a Point due to a Uniform Electric Field
So 3600N/C field acts in the x-axis direction, and the field from the point charge acts in all directions with a value of (9x10^9 x 9.8 x 10^-9)/0.2^2. So what I do is add these two together to find the total electric field in the x-axis direction (let this sum be A), and the field in the y-axis...- slaw155
- Post #5
- Forum: Introductory Physics Homework Help
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Net Electric Field Strength at a Point due to a Uniform Electric Field
So because the uniform field acts perpendicular to the field from the point charge, the electric field at y=0.2m would be just the electric field from the point charge alone? Is my understanding correct?- slaw155
- Post #3
- Forum: Introductory Physics Homework Help
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Net Electric Field Strength at a Point due to a Uniform Electric Field
Homework Statement A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 3600 N/C and is directed in the positive x direction. A point charge -9.8 × 10-9 C is placed at the origin. Find the magnitude of the net electric field at y = +0.20...- slaw155
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- Electric Electric field Electric field strength Field Field strength Net Strength
- Replies: 10
- Forum: Introductory Physics Homework Help
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Diverging and Converging Lenses
Homework Statement A diverging lens (f = –13.0 cm) is located 18.0 cm to the left of a converging lens (f = 31.0 cm). A 3.30-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens Homework...- slaw155
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- Converging Lenses
- Replies: 1
- Forum: Introductory Physics Homework Help
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Sound intensities in hearing aids
Thanks solved it turns out I made a mistake on my calculator.- slaw155
- Post #3
- Forum: Introductory Physics Homework Help
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What is the correct frequency of the reflected ultrasound received by the bat?
A bat uses ultrasound at 40kHz to locate a stationary insect. If bat is flying directly towards the insect at speed of 4m/s at what frequency does the bat receive the ultrasound reflections from the insect? Speed of sound = 340m/s. I went frequency = frequency of source x (velocity of...- slaw155
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- Doppler Doppler effect Frequency
- Replies: 1
- Forum: Introductory Physics Homework Help
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Calculating Object-Lens Distance for Diverging Lens Optics
thanks solved it- slaw155
- Post #3
- Forum: Introductory Physics Homework Help
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Solving Sun Intensity Problem: 685W/m^2 in 6.5 Days
thanks solved it- slaw155
- Post #3
- Forum: Introductory Physics Homework Help
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Sound intensities in hearing aids
What decibel increase does a hearing aid produce if its sound gathering area is 900cm^2, the area of the eardrum is 0.5cm^2, but it only has an efficiency of 5% in transmitting sound to the eardrum? I know sound level = 10log(final intensity/initial intensity), but we've only been given areas...- slaw155
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- Hearing Intensities Sound
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Object-Lens Distance for Diverging Lens Optics
Diverging lens has focal length 6mm and image magnification 0.5. What is the distance between object and lens? I used the fact that distance image to lens/distance object to lens = 0.5 and the lens maker formula with f=-6 and combined the two formula but this gives distance = 18mm, when answer...- slaw155
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- Lens Optics
- Replies: 2
- Forum: Introductory Physics Homework Help
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Solving Sun Intensity Problem: 685W/m^2 in 6.5 Days
Sun emits 153.6 x 10^15 J of energy onto a region that is 20km by 20km in area. The intensity of the sun on this region is 685W/m^2. How many days would it take for the sun to put that amount of energy onto the region? I went intensity = power/area and got to a time of some 44000seconds...- slaw155
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- Intensity Sun
- Replies: 2
- Forum: Introductory Physics Homework Help
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What is the correct way to calculate the doppler effect in this scenario?
A bat uses ultrasound at 40kHz to locate a stationary insect. If bat is flying directly towards the insect at speed of 4m/s at what frequency does the bat receive the ultrasound reflections from the insect? Speed of sound = 340m/s. I went frequency = frequency of source x (velocity of...- slaw155
- Thread
- Doppler Doppler effect Wave
- Replies: 1
- Forum: Introductory Physics Homework Help