Recent content by smyers33

Okay here's what I got, hopefully I'm right. mass = ∫1/(100-x)dx = -ln(|x-100|) solved at 0 and 50 = ln(2) moment = ∫x/(100-x)dx = -(100*ln(|x-100|)+x) solved at 0 and 50 = 50*(2*ln(2)-1) center of mass = moment/mass ≈27.8652 cm ? hopefully :) and if this is correct there is also a...

So all I do is take the integral of x/(100-x)dx going from 0-50, to find the first moment?

Homework Statement A metal rod is 50cm long. Its linear density at the point x cm from the left end is given by the equation p(x)=1/(100-x) gm/cm. Find the mass and center of mass for the rod. Homework Equations mass = \int p(x)dx center of mass = moment / mass The Attempt at a...