Recent content by SnowboardNerd
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Need help with my Swinging Ball problem please
I did it perfectly... all I did wrong was that I unnecessarily squared an sin theta and you faggots couldn't tell me that. this site is useless...- SnowboardNerd
- Post #5
- Forum: Introductory Physics Homework Help
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Need help with my Swinging Ball problem please
**** you all, this website is ********. you guys never actually respond and when you do its useless. suck a cows dick. I'm out.- SnowboardNerd
- Post #4
- Forum: Introductory Physics Homework Help
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Need help with my Swinging Ball problem please
Is there anything else I need to include to get help?- SnowboardNerd
- Post #2
- Forum: Introductory Physics Homework Help
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Need help with my Swinging Ball problem please
Homework Statement A mass m = 16.0 kg is attached to the lower end of a massless string of length L = 63.0 cm. The upper end of the string is held fixed. Suppose that the mass moves in a circle at constant speed, and that the string makes an angle theta = 17o with the vertical, as shown in...- SnowboardNerd
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- Replies: 6
- Forum: Introductory Physics Homework Help
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2 Blocks 1 Pulley - First Time Poster
Yeah, this is not making sense... sorry. Can you please explain it again?- SnowboardNerd
- Post #13
- Forum: Introductory Physics Homework Help
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2 Blocks 1 Pulley - First Time Poster
Yeah, this is not making sense... sorry. Can you please explain it again?- SnowboardNerd
- Post #12
- Forum: Introductory Physics Homework Help
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2 Blocks 1 Pulley - First Time Poster
208.9 cos 29.7 - (5.5 a + 28.3 * -9.8 ) - 0.201 ( 208.9 - sin (29.7) ) = 28.3 - a a = 86.357?- SnowboardNerd
- Post #11
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
F + (0.23)(70cos(26.9)) - (70.6sin(26.9)) = 0 F = 17.6 N Yeah! Thank you very much! I have another thread open too if you would be kind enough to help! https://www.physicsforums.com/showthread.php?p=3529346&posted=1#post3529346- SnowboardNerd
- Post #11
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
F + (0.23)(70cos(26.9)) - (70.6sin(26.9)) = 0 F = 17.6 N Yeah! Thank you very much!I have another thread open too if you would be kind enough to help! https://www.physicsforums.com/showthread.php?p=3529346&posted=1#post3529346- SnowboardNerd
- Post #10
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
I thought you ment Fn... I'm not sure what the variable Fm stands for- SnowboardNerd
- Post #7
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
I think Fn = W... so in the beginning when they said that it's W = 70.6 that means that Fn = 70.6?- SnowboardNerd
- Post #6
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
F - (0.23)(70.6cos(26.9)) - (70.6)sin(26.9)) = 0 F - Kintic Friction - mgSinTheta = 0 ^^ Is that what you meant? Thank you.- SnowboardNerd
- Post #4
- Forum: Introductory Physics Homework Help
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2 Blocks 1 Pulley - First Time Poster
M1: F-T-ukFn = m a (208.9cos(29.7)) - T - 0.201*277.34 = 28.3*a M2: T - mg = m a T - 5.5*9.8 = 5.5 a (T - (5.5*9.8) ) / 5.5 = a ___________________________________ How would I solve for something like this? Two variables?- SnowboardNerd
- Post #9
- Forum: Introductory Physics Homework Help
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2 Blocks 1 Pulley - First Time Poster
Does this suffice?- SnowboardNerd
- Post #7
- Forum: Introductory Physics Homework Help
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Min Force to keep from Slipping
More of my attempt... __________________ Y Direction: Sum F = M * A Fn-mg = 0 Fn = mgcosTheta <---- I got this from breaking gravity into it's components. _________________ X Direction: Sum F = M * A F - Static Friction - mgSinTheta = 0 F = uS*Fm - mgsinTheta _________________ Can you...- SnowboardNerd
- Post #2
- Forum: Introductory Physics Homework Help