Recent content by SolCon

eumyang, I have actually not heard of this term. Thanks for informing me of this. :smile: A quick google search shows that these solutions are those that do not satisfy the original equation. Here, like you have said, x=25 is not the extraneous solution but x=4 is. This is what I've...

Thank you for that nice explanation for both questions. :) About Q.1, I've got the x-values now which are x=4 and x=25. Just one thing though. The answer says that these are actually 5 or -2 which are both the square root of the x-values. Why is this? Is it because of the fact there is...

Thanks for pointing out those mistakes. :) So we'll get: 100 = x^2 - 6x^3/2 + 9x Is that right? If so, then how do we proceed? Also, any thoughts about the second question?

2 questions. Function g(x) and a "set of values of x" issue. Hi to all. I've got 2 questions which are small but I just need to get somethings cleared in them. Alright. Q.1) The function g is defined by g:x ---> x-3(sqrt.x) for x>=0. Solve the equation g(x)=10. For this, I tried 2...

Once I again I thank you for the well structured explanation. It'll take me a while to completely allow the entire thing to penetrate through my skull, but I'm sure I'll get it. Thanks for the help. :)

Apologies for the late reply. Thanks everyone for the responses. :) tiny-tim: Yes, I forgot about that. Was going by doubling the pi value. :) eumyang: I don't know why you can't see the images, maybe something's blocking them at your end? Also, the part where the question asks for a...

Hi to all. :) So I'm having a problem with this question, but in only one part, whereas the other parts of this question were done with correct answers. The only part where I'm having a problem, concerns drawing the graph of y=f(x). Here's the question: Q. The function f is such that f(x) = a...

This was my mistake. :-p I read and typed that part of the page where I had written part (i)'s answer and part (iii)'s solution. Yes, that is exactly what I'm getting. :) Right, but what values do I have to take for x? Do I have to take, for example, cos (pi/2), cos (pi), cos (3pi/2), cos...

Hi. :) Alright, another functions related problem. This question came in 3 parts. I've done the first one but the other 2 are being a problem. Here it is: Q. The function f is such that f(x) = 2 sin^2(x) − 3 cos^2(x) for 0 ≤ x ≤ p. (i) Express f(x) in the form a + b cos^2(x), stating...

Thanks for the reply. :approve: The answer to this question is 12.9. But this was achieved by having in the above equation "μ-10". Multiplying under root 21 with 0.64 then adding 10 will give us this answer. But isn't the formula "x-μ" instead of "μ-x"? You have said that the prob being asked...

Hello to all. Simple question but I'm getting the wrong answer here. Question: The random variable X is normally distributed with mean μ and variance 21.0. Given that P(X > 10.0) = 0.7389, find the value of μ. The equation we'll use is thus: z=(x-μ)/SD So, what I did was: 0.64...

Greetings to all. :smile: Okay, I have 2 simple questions about integration. They are summarized in topic title. 1) This is the figure: http://usera.ImageCave.com/biosyn/qq.PNG It shows a curve y=x^2 and the line y=3+2x. Point A is (3,9) and point B is (-1,1). We have to calculate the area...

I apologize for the late response. -_- However, I just wanted to give my thanks for helping me realize the relation between function and domain and for clearing up the confusion. Appreciate the effort with the graphs too. :biggrin:

Alright. For the above equation, (6-3x)/2x, this is f-1(x). So for f(x) (to get range) we will have y [or f(x)]=6/(3+2x). Seeing as x>=2, we plug in the value of 2 in x, and that is how you have gotten 6/7 as the domain. 6/(3+2(2)) = 6/3+4 = 6/7. This is right or wrong? So, using same...

Thanks for the reply. :) One thing though. f(x) may never equal 0 but what if it was x>=2 or x>=4 instead of x>=0 as the condition? And we used f-1(x)=0 and got x=2? Would we get: for when x>=2) x<=2 for when x>=4) 2<=x<=4 Is this right?