Recent content by solvejskovlund

Sorry for the late reply - I lost my phone - only way of internet access.I don't have any access to make changes to the MC behavior. Hence everything has to be a separate logic block.I'm also thinking of dropping the MC signal. The MC makes its decision based on voltage from a sensor. It would...

I'm need to control a relay in three ways: 1: Forced OFF signal. This is a signal triggered from a MC that I have no access to change. It is a 1 wire output that is normally floating, and pulled to ground for exactly 1 minute when the MC has detected that the relay should turn off. Important...

A unknown x given by another unknown θ that is derived from x, doesn't solve anything. I'm surprised this wasn't straight forward math.

For (5) I had ## x^2 -2R\frac{L}{5}+\frac{L^2}{25}=0 ## Solving (5) for R: ## 2R\frac{L}{5}=x^2+\frac{L^2}{25} ## ## R=x^2\frac{5}{2L}+\frac{L^2}{25}*\frac{5}{2L} ## ## R=\frac{5x^2}{2L}+\frac{L}{10} ## Insert into (4) ## x=(\frac{5x^2}{2L}+\frac{L}{10})*sin(\Theta) ## ##...

Thought you ment something that wasn't already listed. (4) gives ## R=\frac{x}{sin(\Theta)} ## (5) gives ## x^2 + R^2-2R\frac{L}{5}+\frac{L^2}{25}=R^2 ## ## x^2 -2R\frac{L}{5}+\frac{L^2}{25}=0 ## combined: ## x^2 -2* \frac{x}{sin(\Theta)} *\frac{L}{5}+\frac{L^2}{25}=0 ## Having x and θ as...

Uh. I didn't realize I had left out the /2 when using θ. Glad you pointed that out. I don't see which trig relationship you're pointing to.

R-h=R*cos(θ) ## cos(θ)=\frac{R}{R}-\frac{h}{R}=1-\frac{L}{5R} ## Could also be written as ## \frac{L}{5R}=1-cos(θ) ## ## \frac{L}{R}=5-5*cos(θ) ## From before I have: ## \frac{L}{2πR} = \frac{2θ}{2π} = \frac{θ}{π} ## (segment length vs circle length = angle vs circle angle) ## \frac{L}{R} =...

Some formulas I see related: ## \frac{L}{2πR} = \frac{2θ}{2π} = \frac{θ}{π} ## (segment length vs circle length = angle vs circle angle) R2 = x2 + (R-L/5)2 (pythagoras) ## x=R*\sin(\frac{\Theta}{2}) ## Combining these, knowing that x=2c, and h=L/5, I just get the formulas of the wiki as...

I couldn't figure a way to calculate chord (c) without finding the radius (R). Determining the radius turned out to be where I failed in my logic thinking. Thanks to the wiki formulas, now I've also failed using math! Looking at the formulas in the wiki, there is R = h/2 + c2/8h h in my case is...

Thank you. Now I know what to read up on.

Yes And the arc has a constant radius. (It is part of a circle)

Here is a sketch of the shed. There are several locations for lifting points. Winch will be used for lifting as well as horizontal pull (which actually is a slope)

I was playing with a small piece of rope I had on the table, moved it to a curve - circle segment - and figured I wanted to calculate the distance between ends of the curve - and failed. Now I'm confused and embarrassed. Here is what I did: The rope has length L. I put the ends of the rope on a...

Specs for speed and load is given in initial post: 800Nm@5rpm to 10Nm@400rpm That is on the output shaft after gear. I think the gear has to be of worm type because of hanging load. Other gears in addition to the worm gear is a possibility. The only number that is a requirement is the 800Nm...

I know how to use an angle grinder and a drill. I'm sure there are planetary gears with usable ratio. But how would that help? Is there a way to adjust the gear ratio of planetary gears? Maybe if two motors are connected to the planet gear, the difference between their speed can cause variable...