Recent content by spirof

Thanks, I went over the internet and I have found the solution. I have to express as linear combination of the Ar and Atan. It sums up to Ax = Ar cos (90-θ) + Atan sin (90-θ) Ay = -Ar sin (90-θ) + Atan cos (90-θ)

Well between Ar and Ax, If u look at my attached image, you will see that I cannot assume that they are parts of a right angle triangle. Ax seems to long to be the hypothenus of Ar, doesn't it?

Thanks u did put me on the track, I do possesses all the θ already for a definite period of time. Actually, correct if I am wrong, if I have and angle of 1.40 rad, then if if i do pi/2 - 1.4, which will give me something around 0.17 rad. From there, i know that the angle between arad and ax...

Homework Statement The problem is about a rod that is set in a pendulum way but that has an angle high enough so the SHM doesn't apply to it. It starts at Pi/2 until it reachs 0. I was able to find the tangential and radial acceleration about the center of mass but now I need to know the x...