Recent content by sportsguy3675

OK. Thanks :)

A square is inscribed in a circle. As the square expands, the circle expands to maintain the four points of intersection. The perimeter of the square is expanding at the rate of 8 inches per second. Find the rate at which the circumference of the circle is increasing. Perimeter = p...

Oh, I figured it out. Turns out that 141.7 = a . So then using the eccentricity I solved for c and then for b using the relationship between the 3. Then the max is a + c and the min is b - c. :)

Oh, I took the square root to get that. Anyways, what am I suppsed to do then?

OK, so .093 = 1 - \frac{b}{a} and .093^2 = 1 - \frac{b^2}{a^2} But if I rewrite the first I get a = .093a+b That can't be right because I still have 2 variables.

Yeah, I still don't know why that person said that >_>

So what you're saying is that: .093 = \sqrt{1 - \frac{b^2}{a^2}} and .093^2 = 1 - \frac{b^2}{a^2} Right?

Um, a^2 = b^2 + c^2 is the same thing as the formula I posted... But, either way, yout idea is not right. 141.7 million is the mean distance not the distance to any point on the orbit. I think the sun is supposed to be at the focus.

Yeah c^2 = a^2 - b^2

But there is 3 variables...right?

Having trouble with this problem. "The mean distance from the sun to Mars is 141.7 million miles. If the eccentricity of the orbit of Mars is .093, determine the maximum distance that Mars orbits from the sun." So basically what it is asking for is half the length of the major axis right...

Yes it does. So what do I do next?

I don't want coordinates for when the value equals 0. All I want, is to convert the rectangular equation into polar form. So instead of having x and y I need r and \Theta. Currently, I have r^2-3cos\Theta+4sin\Theta=0 but I don't know how to convert the sin and cos into polar form.

Well, actually, I guess they are the same thing, but either way, I don't know how to do it :( As for your question, I don't see a purpose, but my teacher sure does.

Who said anything about coordinates. The polar form of the equation is what I need to achieve.