Recent content by sportsguy3675

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    Related Rates Problem (Check work)

    A square is inscribed in a circle. As the square expands, the circle expands to maintain the four points of intersection. The perimeter of the square is expanding at the rate of 8 inches per second. Find the rate at which the circumference of the circle is increasing. Perimeter = p...
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    Ellipse Word Problem

    Oh, I figured it out. Turns out that 141.7 = a . So then using the eccentricity I solved for c and then for b using the relationship between the 3. Then the max is a + c and the min is b - c. :)
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    Ellipse Word Problem

    Oh, I took the square root to get that. Anyways, what am I suppsed to do then?
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    Ellipse Word Problem

    OK, so .093 = 1 - \frac{b}{a} and .093^2 = 1 - \frac{b^2}{a^2} But if I rewrite the first I get a = .093a+b That can't be right because I still have 2 variables.
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    Ellipse Word Problem

    Yeah, I still don't know why that person said that >_>
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    Ellipse Word Problem

    So what you're saying is that: .093 = \sqrt{1 - \frac{b^2}{a^2}} and .093^2 = 1 - \frac{b^2}{a^2} Right?
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    Ellipse Word Problem

    Um, a^2 = b^2 + c^2 is the same thing as the formula I posted... But, either way, yout idea is not right. 141.7 million is the mean distance not the distance to any point on the orbit. I think the sun is supposed to be at the focus.
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    Ellipse Word Problem

    Yeah c^2 = a^2 - b^2
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    Ellipse Word Problem

    But there is 3 variables...right?
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    Ellipse Word Problem

    Having trouble with this problem. "The mean distance from the sun to Mars is 141.7 million miles. If the eccentricity of the orbit of Mars is .093, determine the maximum distance that Mars orbits from the sun." So basically what it is asking for is half the length of the major axis right...
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    Rectangular Equation to Polar

    Yes it does. So what do I do next?
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    Rectangular Equation to Polar

    I don't want coordinates for when the value equals 0. All I want, is to convert the rectangular equation into polar form. So instead of having x and y I need r and \Theta. Currently, I have r^2-3cos\Theta+4sin\Theta=0 but I don't know how to convert the sin and cos into polar form.
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    Rectangular Equation to Polar

    Well, actually, I guess they are the same thing, but either way, I don't know how to do it :( As for your question, I don't see a purpose, but my teacher sure does.
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    Rectangular Equation to Polar

    Who said anything about coordinates. The polar form of the equation is what I need to achieve.
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