Related Rates Problem (Check work)

  • Thread starter Thread starter sportsguy3675
  • Start date Start date
  • Tags Tags
    Related rates Work
Click For Summary
SUMMARY

The discussion focuses on a related rates problem involving a square inscribed in a circle, where the perimeter of the square expands at a rate of 8 inches per second. The relationship between the perimeter (p) and the diameter (d) of the circle is established as p = 2√2 d. The rate of change of the diameter (dd/dt) is calculated to be 2√2 inches per second, leading to the conclusion that the rate of increase of the circumference (C) of the circle is 2√2π inches per second. The calculations are confirmed to be correct, with a suggestion to use a different variable for clarity.

PREREQUISITES
  • Understanding of related rates in calculus
  • Familiarity with the geometric properties of circles and squares
  • Knowledge of differentiation techniques
  • Ability to interpret and manipulate equations involving rates of change
NEXT STEPS
  • Study the application of related rates in real-world scenarios
  • Learn about implicit differentiation techniques in calculus
  • Explore geometric relationships between shapes and their properties
  • Practice solving additional related rates problems for mastery
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in applying related rates to geometric problems.

sportsguy3675
Messages
45
Reaction score
0
A square is inscribed in a circle. As the square expands, the circle expands to maintain the four points of intersection. The perimeter of the square is expanding at the rate of 8 inches per second.

Find the rate at which the circumference of the circle is increasing.

Perimeter = p
diameter/diagonal = d
circumference = C

p = 2d sqrt2
p = 2sqrt2 d
dp/dt = 2sqrt2 dd/dt
dd/dt = 8 / 2sqrt2
dd/dt = 2sqrt2 in/sec

C = pi d
dC/dt = pi dd/dt
dC/dt = 2sqrt2 pi in/sec

Is that correct for the rate of the circumference?
 
Last edited:
Physics news on Phys.org
Yes. I might recommend using some letter other than "d" to represent the length of the diagonal (so you don't get that "dd/dt" stuff) but you work is correct.
 
OK. Thanks :)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
6K